(y^2-2y+1)+(4y^3-y-5)=

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Solution for (y^2-2y+1)+(4y^3-y-5)= equation:


Simplifying
(y2 + -2y + 1) + (4y3 + -1y + -5) = 0

Reorder the terms:
(1 + -2y + y2) + (4y3 + -1y + -5) = 0

Remove parenthesis around (1 + -2y + y2)
1 + -2y + y2 + (4y3 + -1y + -5) = 0

Reorder the terms:
1 + -2y + y2 + (-5 + -1y + 4y3) = 0

Remove parenthesis around (-5 + -1y + 4y3)
1 + -2y + y2 + -5 + -1y + 4y3 = 0

Reorder the terms:
1 + -5 + -2y + -1y + y2 + 4y3 = 0

Combine like terms: 1 + -5 = -4
-4 + -2y + -1y + y2 + 4y3 = 0

Combine like terms: -2y + -1y = -3y
-4 + -3y + y2 + 4y3 = 0

Solving
-4 + -3y + y2 + 4y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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